Table 4. Comparison of HFE Gene... | American Society of Hematology

Table 4.

Comparison of HFE Gene Frequencies in XLSA to Those in Normal Individuals

Population	XLSA Hemizygotes^4-150			Random Controls^4-151			References
Population	Total Chromosomes	C282Y Alleles	H63D Alleles	Total Chromosomes	C282Y Alleles	H63D Alleles	References
United Kingdom	16	2	4	624	37	81	41, 42
United States	8	1	2	312	19	49	25, 38, 43
Italy	6	1	0	234	2	28	44, 45
France	2	1	1	78	3	13	46-48
Germany	2	0	0	78	3	11	42
The Netherlands	2	0	0	78	2	23	42
Total:	36	5	7	1,404	66	205
At-Risk allele frequency^‡		0.172	0.226		0.055	0.153
χ² =		4.06	0.097		—	—
P =		.044	.449		—	—

Population	XLSA Hemizygotes^4-150			Random Controls^4-151			References
Population	Total Chromosomes	C282Y Alleles	H63D Alleles	Total Chromosomes	C282Y Alleles	H63D Alleles	References
United Kingdom	16	2	4	624	37	81	41, 42
United States	8	1	2	312	19	49	25, 38, 43
Italy	6	1	0	234	2	28	44, 45
France	2	1	1	78	3	13	46-48
Germany	2	0	0	78	3	11	42
The Netherlands	2	0	0	78	2	23	42
Total:	36	5	7	1,404	66	205
At-Risk allele frequency^‡		0.172	0.226		0.055	0.153
χ² =		4.06	0.097		—	—
P =		.044	.449		—	—

F4-150

Calculated from patient data listed in Table 3 omitting family 1 and the heterozygotes.

F4-151

The proportion of normal chromosomes analyzed for the 6 representative populations was kept identical to those for the XLSA populations. The absolute number of chromosomes in each population was set proportional to that for The Netherlands population, which was, relatively, the smallest sample size. The number of C282Y and H63D alleles in each population was calculated using the respective allele frequency found in the particular study.

‡

Calculated as: frequency = [C282Y Alleles]/[(Total Chromosomes) − (H63D Alleles)] and [H63D Alleles]/[(Total Chromosomes) − (C282Y Alleles)], since there is complete linkage disequilibrium between C282Y and H63D.

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