Fig. 3.
Fig. 3. Representative second-step RT-PCR products of the different types of BCR-ABL fusion transcripts detected in leukocytes from normal individuals and non-CML cell lines. The BCR-ABL junction is represented by a double-headed arrow (↔). (A) p210-type transcripts: 1 = BCR ex.b2 ↔ ABL ex.a2 and BCR ex.b3 ↔ ABL ex.a2; 2 = BCR ex.b4 ↔ ABL ex.a2; 3 = BCR ex.b5 ↔ ABL ex.a2; 4 = BCR ex.b2 ↔ ABL ex.a2; 5 = BCR ex.b3 ↔ ABL ex.a2; 6 = BCR ex. e17 ↔ ABL ex.a2; 7 = BCR ex.b5 ↔ ABL ex.a2; 8 = BCR ex.b3 ↔ ABL ex.a2; 9 = BCR ex.b5 ↔ 153 bp of ABL intron 1a + ex.a2; 10 = BCR ex.b5 ↔ ex.a2; 11 = BCR ex.b2 ↔ ABL ex.a2; 12 = BCR ex.b3 ↔ ABL ex.a2; 13 = BCR ex.b4 ↔ ABL ex.a2; 14 = BCR ex.b2 ↔ ABL ex.a2. (B) p190-type transcripts: 1 = BCR ex.e1 ↔ ABL ex.a2; 2 = BCR ex.e1 + 56 bp of intron 1 ↔ ABL ex.a3; 3 = BCR ex.e2 ↔ ABL ex.a3; 4 = BCR ex.5 ↔ ABL ex.a3; 5 = BCR ex.e1 ↔ ABL ex.a2; 6 = BCR ex.e4 ↔ ABL ex.a2; 7 = BCR ex.e1 + 108 bp of intron 1 ↔ ABL ex.a2; 8 = BCR ex.e1 ↔ ABL ex.a2; 9 = BCR ex.e4 ↔ ABL ex.a2; 10 = BCR ex.e1 + 46 bp of intron 1 ↔ ABL ex.a2; 11 = BCR ex.e2 ↔ ABL ex.a2; 12 = BCR ex.e1 + 172 bp of intron 1 ↔ ABL ex.a2; 13 = BCR ex.e1 ↔ ABL ex.a2; 14 = BCR ex.e1 + 246 bp of intron 1 ↔ 213 bp of ABL intron 2 + ex.a3.

Representative second-step RT-PCR products of the different types of BCR-ABL fusion transcripts detected in leukocytes from normal individuals and non-CML cell lines. The BCR-ABL junction is represented by a double-headed arrow (↔). (A) p210-type transcripts: 1 = BCR ex.b2 ↔ ABL ex.a2 and BCR ex.b3 ↔ ABL ex.a2; 2 = BCR ex.b4 ↔ ABL ex.a2; 3 = BCR ex.b5 ↔ ABL ex.a2; 4 = BCR ex.b2 ↔ ABL ex.a2; 5 = BCR ex.b3 ↔ ABL ex.a2; 6 = BCR ex. e17 ↔ ABL ex.a2; 7 = BCR ex.b5 ↔ ABL ex.a2; 8 = BCR ex.b3 ↔ ABL ex.a2; 9 = BCR ex.b5 ↔ 153 bp of ABL intron 1a + ex.a2; 10 = BCR ex.b5 ↔ ex.a2; 11 = BCR ex.b2 ↔ ABL ex.a2; 12 = BCR ex.b3 ↔ ABL ex.a2; 13 = BCR ex.b4 ↔ ABL ex.a2; 14 = BCR ex.b2 ↔ ABL ex.a2. (B) p190-type transcripts: 1 = BCR ex.e1 ↔ ABL ex.a2; 2 = BCR ex.e1 + 56 bp of intron 1 ↔ ABL ex.a3; 3 = BCR ex.e2 ↔ ABL ex.a3; 4 = BCR ex.5 ↔ ABL ex.a3; 5 = BCR ex.e1 ↔ ABL ex.a2; 6 = BCR ex.e4 ↔ ABL ex.a2; 7 = BCR ex.e1 + 108 bp of intron 1 ↔ ABL ex.a2; 8 = BCR ex.e1 ↔ ABL ex.a2; 9 = BCR ex.e4 ↔ ABL ex.a2; 10 = BCR ex.e1 + 46 bp of intron 1 ↔ ABL ex.a2; 11 = BCR ex.e2 ↔ ABL ex.a2; 12 = BCR ex.e1 + 172 bp of intron 1 ↔ ABL ex.a2; 13 = BCR ex.e1 ↔ ABL ex.a2; 14 = BCR ex.e1 + 246 bp of intron 1 ↔ 213 bp of ABL intron 2 + ex.a3.

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